Periodic Patterns and Block Structures in Squared Pell Sequence Modulo 10e
Rima Patel1, Devbhadra Shah2
1Department of Humanities and Social Science, Mahavir Swami College of Polytechnic, Bhagwan Mahavir University, Surat, India
2Department of Mathematics, Veer Narmad South Gujarat University, Surat, India
DOI: https://doi.org/10.51244/IJRSI.2025.120500113
Received: 20 May 2025; Accepted: 30 May 2025; Published: 13 June 2025
In this paper, we investigate the periodic properties of the squared Pell sequence {}, which is defined by the recurrence relation
for all
; with
, where
denotes
th Pell number. For any modulus
, we introduce a novel concept of ‘blocks’ within this sequence by examining the distribution of residues over a single period of the squared Pell sequence. Our results reveal that the length of any given period of the squared Pell sequence comprises either 1 or 2 blocks.
Keywords: Fibonacci sequence, Pell sequence, Periodicity of Pell sequence.
The Fibonacci sequence shows interesting periodic properties under modulo
. Initially, the last digits of Fibonacci numbers seem random, but a clear pattern emerges: the sequence of last digits repeats every 60 numbers. Therefore, the last digits exhibit a periodicity with a cycle length of 60, expressed as
for any
, where
. Koshy [7] proved this using mathematical induction.
In , Kramer and Hoggatt Jr.
established the periodicity of Fibonacci sequence as well as of Lucas sequence when considered modulo
. Patel, Shah [5] considered the periodicity of generalized Lucas numbers and proved the result when the length of its period under modulo
.
This brings in to mind an immediate question – For any given positive integer , does the sequence
is periodic when considered modulo
? In
, Wall
examined the periodic nature of
with respect to any positive integer
and showed that
consistently exhibits periodicity.
Ömür Deveci, Erdal Karaduman proved some elementary results for the periodicity of
. For further details about Pell numbers, one can refer Horadam
and Koshy
.
This listing can be further extended as several articles are available in the literature concerning the periodicity of varied generalizations of the Fibonacci sequence. In the following section, we now consider the periodicity of a new sequence – the squared Pell sequence.
The squared Pell sequence is the sequence which consists of the squares of all the Pell numbers in order.
Definition: The sequence represents the squares of corresponding terms of the sequence
in order. In other words,
; for all
, where
stands for
th Pell number.
It is trivial to note that . We first derive some elementary results for this sequence which will be used further in this paper. The following result gives a recurrence relation which helps to reduce the terms of
into smaller terms.
Lemma :
.
Lemma :
.
Lemma :
.
In the following section we study the periodicity of sequence and obtain some interesting results related with its residues.
In this section, we study in detail about the periodic nature of when considered modulo
. For the detailed insights, one can refer Marc
Definition: By , we mean the sequence of the least non-negative residues of the terms of the squares of terms of the sequence
in order taken modulo
.
As an illustration, we consider 𝑆𝑃(𝑚𝑜𝑑 8) in the following table:
Table 𝟒. 1: 𝑺𝑷(𝒎𝒐𝒅 𝟖)
0 | 1 | 2 | 3 | 4 | 5 | 6 | |
0 | 1 | 4 | 25 | 144 | 841 | 4900 | |
0 | 1 | 4 | 1 | 0 | 1 | 4 |
From the above table, it can be noticed that the sequence 𝑆𝑃(𝑚𝑜𝑑 8) is periodic. Furthermore, it is not difficult to check that 𝑆𝑃4𝑛+𝑖 ≡ 𝑃𝑖(𝑚𝑜𝑑 8); where 𝑛 ≥ 0. This clearly indicates that the period of 𝑆𝑃(𝑚𝑜𝑑 8) is 4.
We now prove several results for the periodic nature of analogues to that of
.
Lemma: The sequence
is always periodic; for any integer
and its starting values
.
We next introduce the notation for the length of period of .
Definition: denotes the length of period of the squared Pell sequence modulo
.
The following are some immediate consequences from the lemmas ,
and the definition of
.
Lemma : (a)
(b)
(c)
(d)
(e)
(f)
(g) ,
.
Fact : Since
is periodic, we will often use the fact that ‘if both
and
holds, then
.
Lemma : For any given integer
, there are infinitely many squared Pell numbers which are divisible by
.
Theorem : If
then
.
Theorem :
, for various values of
, where
and
’s are distinct primes.
Theorem:
.
VALUE OF
In this section, we obtain the value of when
.
Theorem :
.
Proof: We notice that . Therefore,
. For
, we prove the result by induction.
We note that and
. Therefore,
and
. This proves the result for
. We assume that the result holds for some positive integer
. Thus,
;
.
Then by the lemma and
, we have
By lemma , we have
. By taking
and using
, we have
Thus,
Again, by lemma , we have
. Considering
, we get
.
But by , we get
and
. Thus,
and
. By considering modulo
, we have
or
; and
or
. Thus by
, we have
Thus,
Then by the and fact
, we have
Since implies
, we get
Then by combining equation and
, we get
or
.
We shall show that the case is not possible. In fact, we will show that
. More precisely, we will prove that
.
Considering , we have (i)
and (ii)
. Therefore,
is true for
. Let it be true for some integer
. Thus,
. Considering modulo
, we get
or
Then, or
.
Now since , we have
.
Also, .
This gives,
.
We also assume that
(This is because if it is not true then replacing by
, we can say that
is not true. Thus,
which we need to prove.) Taking modulo
, we get
or
. Thus
Now, by lemma , we have
. Considering
, we get
By and
, we thus have
Thus,
This now confirms that ; that means
is not possible. Hence
. This proves the theorem by induction.
VALUE OF
In this section, we obtain the value of for the case
.
Theorem :
Proof: To prove the required result, it is sufficient to prove that
We use induction to prove these results. For , we have
and
.
Thus, is true for
. We next assume that results hold for some positive integer
. That is, let the following holds:
We prove that holds for
also. Therefore, we need to prove that
and
. Now, by lemma
, we have
. By considering
, we get
.
Also, by Koshy , we have
and by lemma
, we have
. Therefore,
. Thus,
By Koshy , we have
.
By considering , we get
. Now, by lemma
, we have
. Also, by lemma
, we have
. Therefore,
Thus,
Using the and fact
, we can now conclude that
Since implies that
. Also, by induction hypothesis, we have
. This gives
Thus using and
, we conclude that
or
.
We finally confirm that the case is not possible. In fact, we show that
. Now by Koshy
, we get
.
Considering , we get
.
Since by Koshy , we have
and
and thus in modulo
, we have
and
. Also, by lemma
and
, we have
and
.
Thus, in modulo , we have
and
. We get
Therefore, . This shows that
is not possible. Hence,
. Thus,
is true for every positive integer
, which proves the required result.
Finally, using theorem and
we easily conclude the following important result.
Theorem :
.
The following result calculates the period of when considered modulo
.
Theorem :
and
; where
and
is any integer.
In the next section, we introduce the notion of blocks within the period of the squared Pell sequence.
In this final section, we study the nature of the blocks within the residues of the squared Pell sequence when considered modulo . We also discuss the distribution of residues within a single period of
. For the detailed insights, one can refer Patel, Shah [4].
Definition: denotes the smallest positive value of index
of squared Pell numbers such that
and
; when
.
Thus, . We call
to be the restricted period of
. Thus
indicates the position of ending of first block which occurs in
. We call the finite sequence
to be the first block occurring in
.
Definition: When , we call
to be without restricted period.
To illustrate these definitions, we consider the following examples.
(i) Since , then clearly
. In this case
will be without restricted period.
(ii) Since , we have
and
. Thus,
. Here
is the first block in
.
(iii) Since , thus we have
and
. Thus,
. Here
is the first block in
.
From last two illustrations, it is seen that the subscript of terms for which and
contains equal number of (that is
number of) terms and the subscripts are in arithmetic progression with common difference
. That is,
and
.
Thus, we can say that , for each positive integer
. Moreover, since
, we say that
where
is some positive integer. Thus,
.
To illustrate this, we consider
.
Then it can be seen that ,
and
. Thus, in this case
and
.
Later we will show that the value of is always either
or
. The following result gives interesting outlook about the divisibility property of suffix
.
Lemma :
if and only if
.
Proof: Let . Then, we have
; for some
.
In view of the above comment, . This gives
.
To prove the converse part, assume that . Then by the definition of
, either
or
. If
then
is true and if
then as
lies in the simple arithmetic progression with first term
and common difference
, we have
. Therefore,
is true in any case. This completes the proof.
The following interesting divisibility property always holds for any arbitrary values of and
.
Theorem :
.
Proof: By the definition of , we have
. Therefore,
is always true. Thus,
also holds. Now for any multiple of
,
th position within the list of residues for
will always contain zero. Thus,
; that is
. Hence,
, as required.
To illustrate this, we consider , In this case we observe that
. When we consider
,
we observe that . Thus,
.
Definition: By , we mean the first positive residue appearing after the blocks in
. That is
and
is the smallest such number.
Since, and
, we have
. Thus,
acts like a multiplier of the first periodic part of
.
To illustrate this, we consider . Then since
, we have
Thus, .
Definition: denote the order of
.
That is and if
then
.
As an illustration, if we once again consider , then
and
. Thus,
.
To illustrate above definitions, we consider the following two examples:
The following resembles the theorem for the sequence
.
Theorem :
Proof: Throughout the proof we consider all the congruences modulo . Suppose that one period of
is partitioned into smaller and finite subsequences
as shown below:
where and every
contains exactly one
.
Clearly each subsequence has
terms and
. Also, in any
, there is exactly one zero. Hence every subsequence
is a multiple of
. More precisely, we have the following congruences:
Now the last term in is
and that of
is
. Also, we have
. Therefore,
. By the similar arguments, we have
Therefore, we have
⋮
.
Therefore, .
Since the order of is
, we rewrite sequence
as follows:
;
with .
Thus can be interpreted as the number of blocks in a single period of
. It now follows easily that
.
The following results will be helpful for the study of blocks within the residues of .
Corollary :
.
Proof: From above theorem, we have and
. Thus, we have
This shows that the term of
is equal to
times the
term of
, when considered modulo
. Also, from the definition of
we conclude that
, when considered modulo
. Therefore, from
and above arguments, we can say that
. This finally gives
.
Corollary :
.
Proof: Since , we write
, as required
Theorem :
or
, for
.
Proof: By Koshy , we have
. Taking
, we get
.
Now, . Also, we know that
and
.
Therefore, by , we have
. Thus, we get
, that is
. Since order of
is
, we finally conclude that
must divide
. Hence, for any
, we have
or
.
We conclude by presenting a table displaying the values of and
for 2 ≤ m ≤ 20.
2 | 2 | 2 | 1 |
3 | 4 | 4 | 1 |
4 | 2 | 2 | 1 |
5 | 6 | 3 | 2 |
6 | 4 | 4 | 1 |
7 | 6 | 6 | 1 |
8 | 4 | 4 | 1 |
9 | 12 | 12 | 1 |
10 | 6 | 6 | 1 |
11 | 12 | 12 | 1 |
12 | 4 | 4 | 1 |
13 | 14 | 7 | 2 |
14 | 6 | 6 | 1 |
15 | 12 | 12 | 1 |
In this article, we studied the length of the novel sequence – squared Pell sequence when considered modulo . We also introduced the ‘blocks’ within the period of this sequence and shown that length of any one period of the squared Pell sequence always contains either 1 or 2 blocks.
Conflict of Interest:
The authors confirm that this article contents have no conflict of interest to declare for this publication.
The authors are grateful to the referees for their valuable suggestions and support This research was conducted without any external funding. Therefore, I would like to respectfully request a waiver for the fee related to my research paper.
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